Baseline

I think there needs to be some context to explain what you are asking for. Are you trying to find the distance between the two inside corners of the red figure?

First off a Baseline is between two control points. The Base is a control point, the Rover by definition is not.

Re-ask your question and does your sketch indicate some type of device?

Paul in PA

X?ý + Z?ý = ???ý?ÿ ?

I agree some clarification would help, as I don't understand the difficulty. Does it have to do with the undimensioned red circles?

Most people with access to a base and rover either can work the geometry and trigonometry, or are employed by someone who can.

@bill93

I'm thinking he needs to know how far it is between two foundation(?) wall corners by setting up the radius of the circle inside them and the radius of the circle shifted down from the corner.?ÿ

Maybe,,,,,,,it can't be the hypotenuse since he already knows that.?ÿ

?ÿ

@bstrand

?ÿAnd X must equal Z?ÿ so delta equals the square root of 2(Z squared) which results in X and Z being 0.7071

times delta.

But, I'm still not getting why this is important if we don't know the offset to the wall faces and the distance to the end of each wall from the points shown.

Posted by: @holy-cow

?ÿAnd X must equal Z?ÿ

If it is isosceles, so that X = Z, why do they have different letters?

With RTK, you really arenƒ??t observing baselines but positions in relation to your base, i.e. +4678.44X, -436.99Y, +0.556Z

Posted by: @robertusa

With RTK, you really arenƒ??t observing baselines but positions in relation to your base, i.e. +4678.44X, -436.99Y, +0.556Z

Which is a VECTOR!

Thank you for the replies.

The setup is as follows A is a Base and it is 10 meters away from the Rover and it is also 10 meters higher than the rover. Therefor X = Z. Z is perpendicular to X therefor the angle is 90 degrees

Both units are stationary and RTK is in progress.

What does the 2 GPS units "see" as the baseline for purposes of RTK? Is it the horizontal distance 10 meters or the hypotenuse 14.14 meters

?ÿ

Thank you

@mightymoe Hi what I am trying to establish is the following: when rtk is performed the time difference between the base and rover is calculated this results in the rover calculating it's distance from the base. This is called the Baseline. How is it calculated and which of the following is the Baseline X, Z or ??? The setup is configured as follows, the Base is place at A and the Rover at B, the horizontal distance X between antenna centers is 10 meters as is the vertical distance Z. Z is perpendicular to X as per the image.

Thank you

Sincerely

@paul-in-pa Hi Paul, the 2 receivers, base and rover are both stationary (static).

@bill93Hi Bill

X is horizontal value and Z vertical value. The distance from the antenna centers horizontally and vertically

@bill93 Hi Bill

Two GPS receivers are deployed statically as in the drawing the red circles indicate the receivers. The Base is deployed at A and the Rover at B exactly 10 meters apart in X and in Y.

What does the RTK process calculate as the Baseline? Is it the horizontal distance 10 meters or the hypotenuse 14.14 meters?

Sincerely

Anton

?ÿ

Posted by: @loyal

Which is a VECTOR!

+1

Regardless of the semantics, they're all vectors, just solved in different ways and for different purposes...

I have derived control point positions from RTK base-rover vectors, and processed static vectors between non-control points, with a "base" receiver and a "roving" receiver.

Is a baseline a vector but a vector not necessarily a baseline? Is everything "control" when processed using static methods? I'm more concerned about results than nomenclature, which can vary quite a bit depending on methods, equipment, and software used.

I am the King of Mis-nomenclature, GPS - GNSS, vector - pseudorange, position - location and accuracy - precision. But a vector and a baseline, never.?ÿ

I agree that the measurement between base and rover is properly referred to as a vector.?ÿSo called because it is a 3d measurement. A baseline is a measurement between any 2 points but is generally defined in 2 dimensions only.

Perhaps we are aiding and abetting a student, once again, who was provided this problem by an instructor.

@mark-mayer

Hang on...

I thought you only need a magnitude and a direction for a vector? In 2D.