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Derivation of Scott's Radius

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dave-lindell
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See attachments

Attached files

scott2.pdf (3.1 KB)  ScottsR.doc (55 KB) 


 
Posted : August 23, 2015 10:45 pm
scott-zelenak
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How about;

R = (abc)/SQRT((a+b+c)(b+c-a)(c+a-b)(a+b-c))


 
Posted : September 2, 2015 6:43 am
MLSchumann
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Lindell equation and Zelenak equation are virtually the same. See pdf.

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MultiplyFactors.pdf (10.4 KB) 


 
Posted : September 2, 2015 9:50 am
scott-zelenak
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The original post;

https://surveyorconnect.com/threads/favorite-formulae.323093/

For the radius point coordinates from the original post;
Xrp=(ya2+xa2-yc2-xc2-(ya-yc)*(ya2+xa2-yb2-xb2)/(ya-yb))/2/(xa-xc-(ya-yc)*(xa-xb)/(ya-yb))
Yrp=(ya2+xa2-yb2-xb2-2*Xrp*(xa-xb))/(ya-yb)/2

and if your " 2 " key is broken;
Xrp=((((yb-xa)/(xb-xa))*((yc-yb)/(xc-xb))*(ya-yc)+((yc-yb)/(xc-xb))*(xa+xb)-((yb-ya)/(xb-xa))*(xb+xc))*0.5/(((yc-yb)/(xc-xb))-((yb-ya)/(xb-xa))))
Yrp=(-1/((yb-ya)/(xb-xa))*(Xrp-((xa+xb)*0.5)))+((ya+yb)*0.5)


 
Posted : September 3, 2015 8:18 am
brad-ott
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Reminds me of a song:

[MEDIA=youtube]_aVRWRQJZoE[/MEDIA]


 
Posted : September 3, 2015 12:46 pm