(.999 x 10) - .999 [tex]does not equal[/tex] 9
You missed the ... which means the 9's go on forever.
Then it works.
and 7 x 13 = 28
[flash width=480 height=385] http://www.youtube.com/v/4W7XJ41JPSc?fs=1&hl=en_US [/flash]
and 7 x 13 = 28
I presume this is another image that I can't see...
and 7 x 13 = 28
> I presume this is another image that I can't see...
Youtube video.
2=1
I'm sure many have seen this old one
Let a=b any arbitrary value
then multiply by a on each side,
a^2 = ab
subtract the same quantity on each side
a^2 - b^2 = ab - b^2
Factor
(a+b)(a-b) = b(a-b)
Cancel out the common term
a+b = b
But a=b so
2b = b
and dividing out b
2=1
Simple algebra. Ain't math wonerful?
Let a = 0.999... then we can multiply both sides by ten yielding 10a = 9.999
No, because you're violating the rules of significant figures for the intermediate steps when you do it this way.
a = 0.999....
(X 10.0)
10a = 9.99 ... <
(-a)
10a - a = 9.99.... - a
9a = 9.99.... - a
a = (9.99 ... - .999 ...) / .999
a = .999
2=2
I get
[tex]a=sqrt(b*a)[/tex]
I diverged at "Cancel out the common term"
and 7 x 13 = 28
Site blocked. www.youtube.com is not allowed on this network.
:-S
