Last one y'all, now Wendell don't have to get up early anymore to censure what the nut posted this time! ????
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Thanks! most of those made me laugh out loud...
Wayne was 86'd because it wasn't dividable by 3; and I didn't even cheat! (use available resources!)
The new symbol in the last row is subject to interpretation.?ÿ My interpretation gives 16 as the final answer.
Do you actually think I can figure out those things I post? I get a headache just looking at ??em. I??ll post the answers around 5 edt. ?????ÿ
Mine 14.
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never trust your eyes at first andsecond sight.
My new answer 98311
my wife gave me 500?ª and told me to buy a xmass tree. and buy something for your own with what??s left she said !
I made the mistake of looking at it on my phone, and got it totally wrong.
How about 1,572,870 ?
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(symbols standing for 6, 4, and 8)
There is another solution using -7, but that is probably messier than you want with fractions.
i noticed you just have to count the segments in the symbols
4^8 x 6 / 4 + 7 as I see it for the moment. Enlighten me!
i noticed you just have to count the segments in the symbols
4^8 x 6 / 4 + 7 as I see it for the moment. Enlighten me!
You are probably right.?ÿ That's the kind of logic these puzzles seem to use.?ÿ The problem is not to do the math, it is to figure out the rules.
I missed the extra line on the last symbol and took it to be another one of the similar ones that are 6.?ÿ Then I got fancy and read the next-to-last symbol as an "inverse" of the "square in circle" symble so called it 1/4.
Answers
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'Great Job You Got It'
This type of code is known as a Caesar Box (Julius Caesar was the first to write codes this way.) To decipher the message, simply divide the code into four groups of four (you can also divide them into groups such as 5 groups of 5 or 6 groups of 6 depending on the number of letters in the phrase), and rearrange them vertically like this...
G T Y O
R J O T
E O U I
A B G T
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Then you read vertically column by column.
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- So that the following plan can be followed, let us number the coins from 1 to 12. For the first weighing let us put on the left pan coins 1,2,3,4 and on the right pan coins 5,6,7,8.
There are two possibilities. Either they balance, or they don't. If they balance, then the different coin is in the group 9,10,11,12. So for our second one possibility is to weigh 9,10,11 against 1,2,3
(1) They balance, in which case you know 12 is the different coin, and you just weigh it against any other to determine whether it is heavy or light.
(2) 9, 10, 11 is heavy. In this case, you know that the different coin is 9, 10, or 11, and that that coin is heavy. Simply weigh 9 against 10; if they balance, 11 is the heavy coin. If not, the heavier one is the heavy coin.
(3) 9, 10, 11 is light. Proceed as in the step above, but the coin you're looking for is the light one.
That was the easy part.
What if the first weighing 1, 2, 3, 4 vs. ?ÿ5, 6, 7, 8 does not balance? Then any one of these coins could be the different coin. Now, in order to proceed, we must keep track of which side is heavy for each of the following weighings.
Suppose that 5,6,7,8 is the heavy side. We now weigh 1, 5, 6 against 2, 7, 8. If they balance, then the different coin is either 3 or 4. Weigh 4 against 9, a known good coin. If they balance then the different coin is 3, otherwise it is 4. The direction of the tilts can tell us whether the offending coin is heavier or lighter.
Now, if 1,5,6 vs 2,7,8 does not balance, and 2,7,8 is the heavy side, then either 7 or 8 is a different, heavy coin, or 1 is a different, light coin.
For the third weighing, weigh 7 against 8. Whichever side is heavy is the different coin. If they balance, then 1 is the different coin. Should the weighing of 1,5, 6 vs 2,7,8 show 1,5,6 to be the heavy side, then either 5 or 6 is a different heavy coin or 2 is a light different coin. Weigh 5 against 6. The heavier one is the different coin. If they balance, then 2 is a different light coin.
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- . 'five' password is not half , rather the sum of digit.
